C++运算符重载的使用方法。 – 作者:yggcwhat

（1）以成员函数的方式，实现运算符“+”的重载，程序运行结果保持不变；

（2）以友元函数的方式，实现运算符“+”的重载，程序运行结果保持不变。

(1):

#include<iostream.h>

class Box

{

public:

Box(){}

Box(int l,int b, int h)

{

length=l;

breadth=b;

height=h;

}

Box operator+(Box& b)

{

Box box;

box.length=length+b.length;

box.breadth=breadth+b.breadth;

box.height=height+b.height;

return box;

}

void print()

{

cout<<“length:”<<length<<endl;

cout<<“breadth:”<<breadth<<endl;

cout<<“height:”<<height<<endl;

}

private:

double length;

double breadth;

double height;

};

int main()

{

Box Box1(1,2,3);

Box Box2(4,5,6);

Box Box3;

Box3=Box1+Box2;

Box3.print();

return 0;

}

(2):

#include<iostream.h>

class Box

{

public:

Box(){}

Box(int l,int b, int h)

{

length=l;

breadth=b;

height=h;

}

friend Box operator+(Box& b,Box& b1);

void print()

{

cout<<“length:”<<length<<endl;

cout<<“breadth:”<<breadth<<endl;

cout<<“height:”<<height<<endl;

}

private:

double length;

double breadth;

double height;

};

Box operator+(Box& b,Box& b1)

{

Box box;

box.length=b1.length+b.length;

box.breadth=b1.breadth+b.breadth;

box.height=b1.height+b.height;

return box;

}

int main()

{

Box Box1(1,2,3);

Box Box2(4,5,6);

Box Box3;

Box3=Box1+Box2;

Box3.print();

return 0;

}

程序1：掌握以类的成员函数重载运算符的使用方法。

源代码：

#include<iostream.h>

class Time

{

private:

int hour;

int minute;

public:

Time(){hour=0; minute=0;}

Time (int h,int m);

Time operator+(Time &t2);

void display();

};

Time::Time(int h,int m)

{

hour=h;

minute=m;

}

Time Time::operator +(Time &t2)

{

Time t;

t.hour=hour+t2.hour;

t.minute=minute+t2.minute;

if(t.minute>=60)

{

t.minute-=60;

t.hour++;

}

return t;

}

void Time::display()

{

cout<<hour<<“小时”<<minute<<“分钟”<<endl;

}

int main()

{

Time t1(3,30),t2(2,40);

Time t;

t=t1+t2;

cout<<“t1+t2+”;

t.display();

return 0;

}

运行结果截图：

程序2：掌握以非成员函数重载运算符的使用方法。

源代码：

运行结果截图：

自定义编程：

定义一个Point类，包含私有的数据成员x，y，按要求完成下面的编程。

（1）重载运算符“<<”和“>>”，用于输出输入Point类的对象。

（2）重载运算符“++”和“–”，实现对Point类对象的自增和自减运算（x和y同时加1或减1），要求同时重载前缀和后缀的形式。

（3）重载运算符“+”和“-”，实现两个点坐标的相加与相减。

源代码：

#include<iomanip>

#include<iostream.h>

class point

{

private:

int x,y;

public:

friend ostream & operator<<(ostream&,point&);

friend istream & operator>>(istream&,point&);

point operator++()

{

x++;

y++;

return *this;

}

point operator++(int)

{

x++;

y++;

return *this;

}

point operator–()

{

x–;

y–;

return *this;

}

point operator–(int)

{

x–;

y–;

return *this;

}

friend point operator+(point &,point &);

friend point operator-(point &,point &);

};

ostream & operator<<(ostream &out,point &a)

{

out<<“x坐标为：”<<a.x<<”  y坐标为：”<<a.y<<endl;

return out;

}

istream & operator>>(istream &in,point &b)

{

in>>b.x;

in>>b.y;

return in;

}

point operator+(point &b,point &b1)

{

point bb;

bb.x=b1.x+b.x;

bb.y=b1.y+b.y;

return bb;

}

point operator-(point &b,point &b1)

{

point bb;

bb.x=b.x-b1.x;

bb.y=b.y-b1.y;

return bb;

}

void getint(int &f)

{

cin>>f;

int a;

a=f;

}

int main()

{

point a,b,f,z;

int c,d,e;

cout<<“请输入两个类对象的x和y坐标：”<<endl;

cout<<“请输入第一个的x和y坐标：”<<endl;

cin>>a;

cout<<a;

cout<<“请输入第二个的x和y坐标：”<<endl;

cin>>b;

cout<<b;

cout<<“请选择：1、两个坐标点自增或自减 2、两个坐标点相加或相减”<<endl;

getint(c);

if(c==1)

{

cout<<“1:自增,2:自减”<<endl;

getint(d);

if(d==1)

{

++a;

b++;

cout<<“自增后x和y坐标为：”<<endl;

cout<<a;

cout<<b;

}

else

{

–a;

b–;cout<<“自减后x和y坐标为：”<<endl;

cout<<a;

cout<<b;

}

}

else

{

cout<<“1:相加 2:相减”<<endl;

getint(e);

if(e==1)

{

f=a+b;

cout<<“相加为：”<<endl;

cout<<f;

}

else

{

z=a-b;

cout<<“相减为：”<<endl;

cout<<z;

}

}

return 0;

}

运行结果截图：

自增：

相加：

来源：freebuf.com 2021-06-03 12:18:39 by: yggcwhat